Hello everyone,
I am trying to use JS to hide buttons. Basically if a checkbox is selected I want to show one box, but if the checkbox isn't selected I want it to show a different one.
So by default I have one field hidden on document load:
$('.Reject').hide();
Next is the code I am using:
function changebuttons() { if ($("#q20 input:checked").val() == 'Yes') { $('.Reject ').show(); $('.Approve').hide(); } else $('.Reject').hide(); $('.Approve').show();
Forgive me if there are syntax errors above, as I only copied a portion. The above code is showing the .Reject button, but is not hiding the .Approve button. Below is the entire JS I have written for this form.
//this code hides the next add another user field. It will show when one user is added. $(document).ready(function() { $('.Reject').hide(); //hide the Comment + Add User(s) button by default toggleFields(); //call this first so we start out with the correct visibility depending on the selected form values //this will call our toggleFields function every time the selection value changes $("#q21").change(function() { toggleFields(); }); $("#q20").change(function() { changebuttons(); }); //this toggles the visibility of our parent permission fields depending on the current selected value function toggleFields() { if ($("#q21 option:selected").text() == '') $("#q25, #q22") .hide(); else $("#q25, #q22").show(); //this code changes the button from Comment to Comment + Add User(s) if the add user to form is chosen changebuttons(); //call this first so we start out with the correct visibility depending on the selected form values //this will call our toggleFields function every time the selection value changes } function changebuttons() { if ($("#q20 input:checked").val() == 'Yes') { $('.Reject ').show(); $('.Approve').hide(); } else $('.Reject').hide(); $('.Approve').show(); } });
Thanks in advance if we get a solution. Forgive me if it is a noob mistake :(