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Question

Token expressions for pattern matching to capture number with leading zeroes

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Updated November 12, 2015

asked on November 12, 2015

When I setup my expression to capture a number that starts with a zero as soon as I go past the 4th digit it drops the leading zero. What do I need to put here in order to get the leading zero? See below example:

Thanks,

Robin

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Answer

SELECTED ANSWER

replied on November 12, 2015 • Show version history

EDIT: your problem is the "." after the #\s*. <--that last period is accounting for the first character after the space.

I was able to get it using: # (\d+)

I used the # as an anchor, then said I am looking for at least 1 digit after.

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Replies

replied on November 12, 2015

Darrell,

Thanks!!! I knew it was something simple I was doing wrong!

Appreciate it!

Robin

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Asked November 12, 2015
Updated November 12, 2015
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