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Question

How do i show\hide the Reject button based on a choice in a dropdown that is not in a table?

Forms

Updated August 5, 2015

asked on August 5, 2015 • Show version history

I need to hide the Reject button then show it if a dropdown field contains a value, or is not blank.

For reference i have attached what i have been trying to use and alter to no avail.

$(document).ready(function() {
$('.Reject').hide();
  $('.Target').on('change', function();
if ($('.Target input').val()! == '') {
      $('.Reject').show();
    } else {
      $('.Reject').hide();
    }
});

0 0

Answer

SELECTED ANSWER

replied on August 5, 2015

There are some syntax errors in your Javascript. Try

$(document).ready(function() {
  $('.Reject').hide();
  $('.Target select').on('change', function() {
    if ($('.Target select').val() != '') {
      $('.Reject').show();
    } else {
      $('.Reject').hide();
    }
  });
});

1 0

Replies

replied on August 5, 2015

Thank you very much! I am still learning JavaScript and appreciate all the help I have received on the Answers website.

0 0

replied on August 5, 2015

You're welcome. That's what we're here for.

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Asked August 5, 2015
Updated August 5, 2015
149 views