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Question

initialize dropdown field

Forms

Updated October 1

asked on September 29

Hello everyone. Could you help me with this form issue to initialize a dropdown field? In the classic version of the form, a statement similar to $('#q17 option').remove(); is used in JavaScript to delete all entries. However, in the new form, I can't find a statement that allows (initializing) deleting all entries in the field. There are only the add, replace, and remove options (the latter for each entry).
Is there another method?

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Replies

replied on October 1

I didn't test either of these idea, but...

I believe the Replace option with an empty array should do it.

LFForm.changeFieldOptions( { fieldId: 17 }, [], "replace" );

If that doesn't work, you could try replacing it with a single value and then deleting that value.

async function clearDropdown() {
  await LFForm.changeFieldOptions( { fieldId: 17 }, [{label: "New Label", value: "Choice_1"}], "replace" );
  LFForm.changeFieldOptions( { fieldId: 17 }, [{label: "New Label"], "remove" );
}
clearDropdown();

Once again, I didn't test either of those code samples, I don't think I've ever had a need to completely clear every option from a drop-down field.

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Asked September 29
Updated October 1
66 views