Question

Display if workflow is an invoked workflow

Workflow Ideas

Updated November 15, 2018

asked on November 14, 2018

Hi All,

Is there a way to see within a workflow, if the workflow you're looking at is configured in another workflow to be invoked?

If not could I make this a feature request please?

It does tell you if you try to delete the workflow, but would be nice to have it displayed somewhere, so if you're trying to un-ravel workflows you know it's an invoked workflow.

Cheers!

1 0

Replies

replied on November 14, 2018

There are two ways that I have found of doing this:

First, within the WF Designer using the Edit->Find - Whose properties contain Your_Workflow_Name
The downside of that is it will only search WF that are currently open in the designer.

Second is querying the WF database:

SELECT TOP (1000) 
workflow_name
,designer_code
,last_update
,version
 FROM [LFWorkFlow].[dbo].[workflow_code] WF
 join [LFWorkFlow].[dbo].[index_workflow_name] WFN on WF.workflow_id = WFN.workflow_id
 where designer_code like '%<Name>YOUR WORKFLOW NAME HERE/Name>%<Parameters />%'

If you look at the designer_code field of a workflow, it's an XML file. The 'Invoke Workflow' activity has a format within the XML field similar to:
<Workflow>
<Id>-1</Id>
<Name>Your Workflow Name Here</Name>
<Parameters />
</Workflow>
Thus searching for: '%<Name>YOUR WORKFLOW NAME HERE/Name>%<Parameters />%'

Hopefully that helps ....

3 0

replied on November 15, 2018

Thanks Andrew, very useful, however I feel this should be something that is offered 'out of the box'.

2 0

replied on November 14, 2018

That would be handy! The best you could do in the mean time is make a note in workflow x that it is invoked by workflow y.

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Display if workflow is an invoked workflow

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